REST Interface XML, request / response, possibilities

Question

I have received from the customer. Three requests ToDo:

Server: sapbcprod1.xc-automation.co.at Port: 8087

Folder: /invoke/COATING/

User (Base64): COAT

Password (Base64): to be defined Encoding: UTF-8

A) Replace data


	
		
			#_DATA_#

B) Replace data


	
		
			#_DATA_#

C) Create automatically

Now I should send this request to a REST server as a request using Replace #DATA#

How can I do this, solve this? HttpClient? How I can serialize and deserialize with XML? The most samples are JSON

Accepted Answer

Hi @Noah Aas , Welcome to Microsoft Q&A,

You can use the HttpClient class from the System.Net.Http namespace. Here's a step-by-step guide to achieve this:

Create the XML content: You'll need to create an XML string that you want to send in the POST request.

Set up the HttpClient: Initialize an instance of the HttpClient.

Create the HttpContent: Wrap the XML string in a StringContent object and set the appropriate media type.

Send the POST request: Use the PostAsync method of HttpClient to send the request.

Handle the response: Process the response from the server.

Here's a complete example:

using System;
using System.Net.Http;
using System.Text;
using System.Threading.Tasks;

class Program
{
    static async Task Main(string[] args)
    {
        // Your XML string
        string xmlData = @"Hello, World!";

        // The URL to send the POST request to
        string url = "https://example.com/api/endpoint";

        // Create a new HttpClient instance
        using (HttpClient client = new HttpClient())
        {
            // Set the content type to XML
            HttpContent content = new StringContent(xmlData, Encoding.UTF8, "application/xml");

            // Send the POST request
            HttpResponseMessage response = await client.PostAsync(url, content);

            // Ensure the response was successful, or throw an exception
            response.EnsureSuccessStatusCode();

            // Read the response content
            string responseContent = await response.Content.ReadAsStringAsync();

            // Print the response
            Console.WriteLine(responseContent);
        }
    }
}

Best Regards,

Jiale

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